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Posts Tagged ‘function’

IMC 2016 – Day 2 – Problem 8

July 28, 2016 2 comments

Problem 8. Let {n} be a positive integer and denote by {\Bbb{Z}_n} the ring of integers modulo {n}. Suppose that there exists a function {f:\Bbb{Z}_n \rightarrow \Bbb{Z}_n} satisfying the following three properties:

  • (i) {f(x) \neq x},
  • (ii) {x = f(f(x))},
  • (iii) {f(f(f(x+1)+1)+1) = x} for all {x \in \Bbb{Z}_n}.

Prove that {n \equiv 2} modulo {4}.

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IMC 2016 – Day 1 – Problem 1

July 27, 2016 Leave a comment

Problem 1. Let {f:[a,b] \rightarrow \Bbb{R}} be continuous on {[a,b]} and differentiable on {(a,b)}. Suppose that {f} has infinitely many zeros, but there is no {x \in (a,b)} with {f(x)=f'(x) = 0}.

  • (a) Prove that {f(a)f(b)=0}.
  • (b) Give an example of such a function.

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There isn’t such a function

February 9, 2012 2 comments

Prove that there is no continuous function f: \Bbb{R} \to \Bbb{R} such that f(\Bbb{Q}) \subset \Bbb{R}\setminus \Bbb{Q} and f(\Bbb{R}\setminus \Bbb{Q}) \subset \Bbb{Q}.

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Categories: Analysis, Olympiad Tags: ,

Number of even images is very small

June 2, 2011 Leave a comment

I found on Math Stack Exchange a generalisation of a problem I proposed in the Romanian Mathematical Olympiad:

Let f:[0,1]\to [0,1]  be a continuous function such that f(0)=0 and f(1)=1. Moreover assume f^{-1}(\{x\}) is finite for all x. Prove that E:=\{x\in [0,1]: |f^{-1}(\{x\})|\,\mbox{ is even} \} is countable.

My problem was to prove that there doesn’t exist a function f:\Bbb{R} \to \Bbb{R} with the property that the equation f(x)=y has an even number of solutions for all y \in \Bbb{R}.

Categories: Analysis Tags:

Function on Subsets

April 29, 2010 Leave a comment

Let f:2^S \to \mathbb{R} be a function defined on the subsets of a finite set S. Prove that if f(A)=f(S\setminus A) and \max \{f(A),f(B)\} \geq f(A\cup B) for all subsets A,B \subset S, then f assumes at most |S| distinct values.
Miklos Schweitzer, 2001

Reccurent function sequence SEEMOUS 2010

April 26, 2010 Leave a comment

Suppose f_0:[0,1]\to \mathbb{R} is a continuous function, and define the sequence (f_n)_n, f_n:[0,1]\to \mathbb{R} in the following way:

f_n(x)=\int_0^x f_{n-1}(t)dt,\ \forall x \in [o,1].

a) Prove that the series \sum_{n\geq 0}f_n(x) converges for any x \in [0,1].

b) Find an explicit formula in terms of x for the above series.

Seemous 2010, Problem 1

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Cute Problem with functions

January 21, 2010 Leave a comment

Let A\subset \mathbb{C} and f:A\rightarrow A A function. Define f_1=f and f_{k+1}=f_k\circ f,\ (\forall)k \in \mathbb{N}^*. Assume that (\exists) \alpha,\ \beta>0 with \alpha+\beta =1 and m,\ n\in \mathbb{N}^* coprimes ( \gcd(m,n)=1), such that \alpha f_m(x)+\beta f_n(x)=x,\ (\forall)x\in A. Find all functions f in the following cases:

i) A=\mathbb{N}.

ii) (\exists)a\in \mathbb{C}^*,\ p\in \mathbb{N}^* such that A=\{z\in \mathbb{C}\ |\ z^p=a\}.

iii) Any set A\subset \mathbb{C} such that there are no three collinear points in A.

Measurable function again

January 7, 2010 2 comments

Suppose f:[a,b]\to \mathbb{R} is a measurable function. Prove that there exists a sequence of polynomials (P_n) such that P_n \to f almost uniformly, which means that for any \varepsilon >0, we can find a set A_\varepsilon with measure smaller than \varepsilon such that P_n \to f uniformly on [a,b]\setminus A_\varepsilon.
Hint: Use Lusin’s theorem and Weierstrass’ approximation theorem, for continuous functions.

Lusin’s Theorem

January 6, 2010 Leave a comment

Suppose f is measurable and finite valued on E, with E of finite measure. Then for every \varepsilon >0 there exists a closed set F_\varepsilon \subset E, with m(E\setminus F_\varepsilon) \leq \varepsilon and such that f | _{F_\varepsilon} is continuous.

This theorem states that any measurable function in a space with finite measure can be made almost continuous. Littlewood said that Every measurable function is nearly continuous.

Egorov’s Theorem

January 6, 2010 Leave a comment

Suppose (f_k) is a sequence of measurable functions defined on a measurable set E with m(E)<\infty , we can find a closed set A_\varepsilon \subset E such that m(E\setminus A_\varepsilon)\leq \varepsilon and f_k \to f uniformly on E\setminus A_\varepsilon.

This theorem states that in spaces with finite measure, almost everywhere convergence is equivalent to almost uniformly convergence.

Jensen convexity

October 26, 2009 Leave a comment

A function defined on an interval I \subset \mathbb{R} (with non-void interior) is called \lambda-convex for a \lambda \in (0,1) if f(\lambda x + (1-\lambda) y) \leq \lambda f(x)+(1-\lambda)f(y),\ \forall x,y \in I.

The function f defined on an interval is called convex if it’s \lambda-convex for all \lambda \in (0,1). A function is called Jensen convex if it is \frac{1}{2}-convex.

Prove that any \lambda-convex continuous function is \frac{1}{2} convex, any convex function is continuous on the interior of its definition interval. Furthermore, if f is Jensen convex and continuous, then f is convex. Therefore, if f is continuous and \lambda convex then f is convex.

Prove that there exist \lambda-convex functions which are not convex.

Interesting property for a differentiable function

October 1, 2009 Leave a comment

Prove that if f : \mathbb{R} \to \mathbb{R} is a differentiable function on \mathbb{R}, then the set of continuity points of f^\prime is dense in \mathbb{R}.